6-(2c-1)^2=(3+2c)(3-2c)

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Solution for 6-(2c-1)^2=(3+2c)(3-2c) equation: 



6-(2c-1)^2=(3+2c)(3-2c)

We move all terms to the left:

6-(2c-1)^2-((3+2c)(3-2c))=0

We add all the numbers together, and all the variables

-(2c-1)^2-((2c+3)(-2c+3))+6=0

We multiply parentheses ..

-((-4c^2+6c-6c+9))-(2c-1)^2+6=0



We calculate terms in parentheses: -((-4c^2+6c-6c+9)), so:

(-4c^2+6c-6c+9)

We get rid of parentheses

-4c^2+6c-6c+9

We add all the numbers together, and all the variables

-4c^2+9

Back to the equation:

-(-4c^2+9)



We get rid of parentheses

4c^2-(2c-1)^2-9+6=0

We add all the numbers together, and all the variables

4c^2-(2c-1)^2-3=0

We move all terms containing c to the left, all other terms to the right

4c^2-(2c-1)^2=3

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